80 lines
3.4 KiB
Markdown
80 lines
3.4 KiB
Markdown
# Sort by Machine
|
|
Analysis generated on: 4/2/2025 10:11:37 AM
|
|
---
|
|
## SQL Statement
|
|
```sql
|
|
SELECT Machines.MachineName, Machines.PartNumber, Machines.CycleTime, Machines.Prime, Machines.Tool, [Util Make Duplicate Revision Remover 2].prt, [Util Make Duplicate Revision Remover 2].Rev INTO [Sorted By Machines 1]
|
|
FROM [Util Make Duplicate Revision Remover 2] LEFT JOIN Machines ON [Util Make Duplicate Revision Remover 2].PN = Machines.PartNumber
|
|
GROUP BY Machines.MachineName, Machines.PartNumber, Machines.CycleTime, Machines.Prime, Machines.Tool, [Util Make Duplicate Revision Remover 2].prt, [Util Make Duplicate Revision Remover 2].Rev
|
|
HAVING (((Machines.MachineName)=[Forms]![Sorted by Machine]![Machine Name]))
|
|
ORDER BY Machines.PartNumber, [Util Make Duplicate Revision Remover 2].prt;
|
|
|
|
```
|
|
## Dependencies
|
|
- [[Tables/Machines]]
|
|
## Parameters
|
|
- [Forms]![Sorted by Machine]![Machine Name] (Empty)
|
|
## What it does
|
|
**SQL Code Description**
|
|
==========================
|
|
|
|
### Overview
|
|
|
|
This SQL code retrieves data from two tables: `[Util Make Duplicate Revision Remover 2]` and `Machines`. The query joins these tables on a common column (`PartNumber`) and filters the results based on specific conditions.
|
|
|
|
### SQL Breakdown
|
|
|
|
#### SELECT Clause
|
|
```sql
|
|
SELECT
|
|
Machines.MachineName,
|
|
Machines.PartNumber,
|
|
Machines.CycleTime,
|
|
Machines.Prime,
|
|
Machines.Tool,
|
|
[Util Make Duplicate Revision Remover 2].prt,
|
|
[Util Make Duplicate Revision Remover 2].Rev INTO [Sorted By Machines 1]
|
|
```
|
|
This selects the following columns:
|
|
|
|
* `MachineName` from the `Machines` table
|
|
* `PartNumber`, `CycleTime`, `Prime`, and `Tool` columns from the `Machines` table
|
|
* `prt` (a column with a name containing " prt") from the `[Util Make Duplicate Revision Remover 2]` table
|
|
* `Rev` (a column with a name containing " Rev") from the `[Util Make Duplicate Revision Remover 2]` table
|
|
|
|
The `INTO [Sorted By Machines 1]` clause creates an alias for the result set.
|
|
|
|
#### JOIN Clause
|
|
```sql
|
|
FROM [Util Make Duplicate Revision Remover 2]
|
|
LEFT JOIN Machines ON [Util Make Duplicate Revision Remover 2].PN = Machines.PartNumber
|
|
```
|
|
This joins the `[Util Make Duplicate Revision Remover 2]` table with the `Machines` table on the common column `PartNumber`. The `LEFT JOIN` ensures that all records from the left table (`[Util Make Duplicate Revision Remover 2]`) are included in the result set, even if there is no match in the right table (`Machines`).
|
|
|
|
#### GROUP BY Clause
|
|
```sql
|
|
GROUP BY
|
|
Machines.MachineName,
|
|
Machines.PartNumber,
|
|
Machines.CycleTime,
|
|
Machines.Prime,
|
|
Machines.Tool,
|
|
[Util Make Duplicate Revision Remover 2].prt,
|
|
[Util Make Duplicate Revision Remover 2].Rev
|
|
```
|
|
This groups the result set by all selected columns.
|
|
|
|
#### HAVING Clause
|
|
```sql
|
|
HAVING (((Machines.MachineName)=[Forms]![Sorted by Machine]![Machine Name]))
|
|
```
|
|
This filters the grouped result set to include only rows where the `MachineName` column in the `Machines` table matches a specific value from the `[Forms]!...` field. The exact value is not specified in this code snippet, but it appears to be a lookup value provided by a form control.
|
|
|
|
#### ORDER BY Clause
|
|
```sql
|
|
ORDER BY
|
|
Machines.PartNumber,
|
|
[Util Make Duplicate Revision Remover 2].prt;
|
|
```
|
|
This sorts the final result set by the `PartNumber` column from the `Machines` table and then by the `prt` column from the `[Util Make Duplicate Revision Remover 2]` table.
|