PSLine2000Documentation/Queries/create all parts list.md

create all parts list

Analysis generated on: 4/2/2025 9:58:29 AM

SQL Statement

SELECT Left([partnumber],7) AS Expr1 INTO temp1
FROM Process
GROUP BY Left([partnumber],7), Left([partnumber],1)
HAVING (((Left([partnumber],1))<="9"));

Dependencies

• Tables/Process

Parameters

• None

What it does

SQL Code Description

This SQL code performs a complex operation on the Process table, grouping data based on specific conditions and formatting the result.

Step 1: Selecting Data

SELECT 
    Left([partnumber],7) AS Expr1
FROM Process

• The code selects data from the PartNumber column of the Process table.
• The Left() function is used to extract a specified number of characters from the left side of the string.
• In this case, it extracts the first 7 characters from each part number.

Step 2: Grouping Data

GROUP BY 
    Left([partnumber],7), 
    Left([partnumber],1)

• The extracted data is grouped by two different subsets of the PartNumber column:
  • Left([partnumber],7): Extracts the first 7 characters from each part number.
  • Left([partnumber],1): Extracts the first character from each part number.

Step 3: Filtering Data

HAVING (((Left([partnumber],1))\u003c="9"))

• The code applies a filter to the grouped data:
  • It checks if the first character of each part number (Left([partnumber],1)) is less than or equal to 9.
  • Only groups with this condition are included in the result.

Step 4: Storing Result

INTO temp1

• The result is stored in a temporary table named temp1.

Example Output

The final result will be a table with two columns:

Expr1
PartNumber7

Where each row contains the first 7 characters of a part number from the Process table that meets the specified conditions.

Note: The actual output may vary depending on the data in the Process table.