# Machines_Crosstab Analysis generated on: 4/2/2025 10:02:02 AM --- ## SQL Statement ```sql TRANSFORM First(Machines.CycleTime) AS FirstOfCycleTime SELECT Machines.PartNumber, Left([PartNumber],7) AS Part, Max(IIf([Prime],[MachineName])) AS PrimaryMachine, Format(Max(IIf([Prime],[Cycletime])),"0.0") AS StdTime FROM Machines GROUP BY Machines.PartNumber PIVOT Machines.MachineName; ``` ## Dependencies - [[Tables/Machines]] ## Parameters - *None* ## What it does **SQL Code Description** ========================== ### Overview This SQL code transforms the `Machines` table by performing several operations: 1. **Selecting first occurrence of cycle time**: It selects the first record from each group based on the `PartNumber`. 2. **Extracting part number**: It extracts the first 7 characters from the `PartNumber`. 3. **Identifying primary machine**: It identifies the maximum value in the `MachineName` column for each `PartNumber`, considering only records where `[Prime] = TRUE`. If no such record exists, it returns an empty string. 4. **Calculating standard time**: It calculates the maximum cycle time for each `PartNumber` and formats it as a decimal value with two places. ### Detailed Breakdown #### First Section: SELECT Statement ```sql SELECT Machines.PartNumber, Left([PartNumber],7) AS Part, Max(IIf([Prime],[MachineName])) AS PrimaryMachine, Format(Max(IIf([Prime],[Cycletime])), "0.0") AS StdTime FROM Machines GROUP BY Machines.PartNumber ``` * This section selects the required columns from the `Machines` table. * It groups the results by the `PartNumber`. * The `Left([PartNumber], 7)` function extracts the first 7 characters from the `PartNumber`. #### Second Section: TRANSFORM Statement ```sql TRANSFORM First(Machines.CycleTime) AS FirstOfCycleTime ``` * This section transforms the results by selecting the first occurrence of `CycleTime` for each group based on the `PartNumber`. #### Final Section: PIVOT Statement ```sql PIVOT Machines.MachineName; ``` * This section pivots the results, rotating the columns to match the unique values in the `MachineName` column. ### Result The final result is a table with the following structure: | Part | Primary Machine | Std Time | | --- | --- | --- | | ... | ... | ... | Each row represents a part number, and the columns contain the extracted part number, primary machine name, and standard time value. The `PrimaryMachine` column contains the maximum machine name for each part number where `[Prime] = TRUE`, and the `StdTime` column contains the formatted maximum cycle time for each part number.